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Electrical Engineering / Electronics Engineering Technology

Analog Devices and Circuits Lab Course (EE 212)

JFET Characteristics and Biasing Lab - Table of Contents

**** 01/30/97 19:57:12 EvaluationPSpice
JFET Output Characteristics (FET #1)

CIRCUIT DESCRIPTION
RD 4 3 4. 7K
VDD 4 0 15V
VGS 1 0 1.25V
JX 3 2 0 JFET
RG 2 1 1MEG
.MODEL JFET NJF (LAMBDA 6.35E 3 BETA 510.4E 6 VTO 2.5V)
.DC VGS 1.25V 1.25V 0.1
.OP
.OPTIONS NOPAGE
.PRINT DC V(3,O), I(RD)
.END
Junction FET MODEL PARAMETERS

JFET NJF
VTO 2.5
BETA 510.4000OOE 06
LAMBDA 6.350000E 03

DC TRANSFER CURVES, TEMPERATURE = 27.000 DEG C
VGS 1.250E+00
V (3, 0) 1.099E+01
1 (RD) 8.5329 04

SMALL SIGNAL BIAS SOLUTION, TEMPERATURE = 27.000 DEG C
NODE (1) VOLTAGE -1.2500
NODE (2) VOLTAGE -1.2500
NODE (3) VOLTAGE 10.9900
NODE (4) VOLTAGE 15.0000

VOLTAGE SOURCE CURRENTS
NAME - CURRENT
VDD = 8.532E 04
VGS = 1.351E 11

TOTAL POWER DISSIPATION = 1.28E 02 WATTS

OPERATING POINT INFORMATION, TEMPERATURE = 27.000 DEG C

* * * * JFETS
NAME = JX
MODEL = JFET
ID = 8.53E 04
VGS = 1.25E+00
VDS = 1.10E+01
GM = 1.37E 03
GDS = 5.06E 06
CGS = 0.00E+00
CGD = 0.00E+00
JOB CONCLUDED
TOTAL JOB TIME 2.42

**** 01/30/97 19:32:01 EvaluationPSpice
JFET Output Characteristics (FET #2)

CIRCUIT DESCRIPTION
RD 3 2 4. 7K
VDD 3 0 15V
JX 2 1 4 JFET
RG 1 0 1MEG
RS 4 0 1.22K
.MODEL JFET NJF (LAMBDA 3.043 3 BETA 510.4E 6 VTO= 2.5V)
.DC VDD 15V 15V 0.1
.Op
.OPTIONS NOPAGE
.PRINT DC V(2,4), I(RD)
.END
Junction FET MODEL PARAMETERS

JFET NJF
VTO 2.5
BETA 510.4000009 06
LAMBDA 3.0400009 03

DC TRANSFER CURVES, TEMPERATURE = 27.000 DEG C
VDD 1.50@E+01
V(2,4) 9.389E+00
I (RD) 9.47SE 04

SMALL SIGNAL BIAS SOLUTION, TEMPERATURE = 27.000 DEG C
NODE (1) VOLTAGE 11.72E 06
NODE (2) VOLTAGE 10.5450
NODE (3) VOLTAGE 15.0000
NODE (4) VOLTAGE 1.1563

VOLTAGE SOURCE CURRENTS
NAME - CURRENT
VDD = 9.478 04

TOTAL POWER DISSIPATION = 1.42E 02 WATTS

OPERATING POINT INFORMATION, TEMPERATURE = 27.000 DEG C

* * * * JFETS
NAME = JX
MODEL = JFET
ID = 9.48E 04
VGS = 1.16E+00
VDS = 9.39E+00
GM = 1.41E 03
GDS = 2.80E 06
CGS = 0.00E+00
CGD = 0.00E+00
JOB CONCLUDED
TOTAL JOB TIME 2.09

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